Matematika Sekolah Menengah Pertama tentukan hasil dibawah ini!!

tolong huhuhu mo nangis aja ​

tentukan hasil dibawah ini!!

tolong huhuhu mo nangis aja ​

EkspoNEN
sifat :
[tex]a^m. a^n = a^{m+n}\\a^m : a^n = a^(m-n)\\(a^m)^n = a^{mn}\\a^{-m) = \frac{1}{m}[/tex]

Penjelasan dengan langkah-langkah:

a. (3²)⁻⁴ = 3⁻⁸ = [tex]\frac{1}{3^8 } = \frac{1}{6.561}[/tex]

b. (-2²)⁻³ = -(2)⁻⁶

[tex]= -\dfrac{1}{2^6} = - \dfrac{1}{64}[/tex]

c. (4a⁻³)⁻³ = 4⁻³ a⁹

[tex]=\dfrac{a^9}{4^3} = \dfrac{a^9}{64}[/tex]

d. (-5 a⁻²)⁻³ = (-5)⁻³. (a)⁶

 [tex]=\dfrac{1}{(-5)^3}. a^6 = \dfrac{a^6}{-125}\\= -\dfrac{a^6}{125}[/tex]

e.  (2a² b³)⁻⁶ = 2⁻⁶. a⁻¹² .b⁻¹⁸

[tex]= \dfrac{1}{2^6.a^{12}. b^{18}}[/tex]

f. (3a³ b⁻⁴)⁻⁵ =  3⁻⁵. a⁻¹⁵ . b²⁰

[tex]=\dfrac{b^{20}}{3^5. a^{15}}[/tex]

[tex]=\dfrac{b^{20}}{243. a^{15}}[/tex]

g. (-5 x³ y⁵)⁻⁴ = (-5)⁻⁴ . x⁻¹². y²⁰

[tex]= \dfrac {y^{20}}{(-5)^4.x^{12}}[/tex]

[tex]= \dfrac {y^{20}}{625.x^{12}}[/tex]

h. (-4. x⁻⁵. y⁴)⁻⁵= (-4)⁻⁵. x²⁵. y⁻²⁰

[tex]= \dfrac{x^{25}}{(-4)^5 . y^{20}}[/tex]

[tex]= \dfrac{x^{25}}{-1.024 . y^{20}}[/tex]

[tex]= - \dfrac{x^{25}}{1.024 . y^{20}}[/tex]

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